C2H3O2NH4 (Ammonium acetate) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of C2H3O2NH4 (Ammonium acetate). Suppose the molecular weight of C2H3O2NH4 is M(C2H3O2NH4). Now we have to divide the gram weight by molecular mass of Ammonium acetate. Then the result gives us a mole number.
mole number of C2H3O2NH4 (Ammonium acetate) = {(grams weight of C2H3O2NH4) ÷ Molecular mass of C2H3O2NH4}
= {w÷ M(C2H3O2NH4)} [suppose w is grams weight of Ammonium acetate ]
Example: Suppose a sample of C2H3O2NH4 has 79.04 grams. Now we have to calculate the mole number of the C2H3O2NH4.
Ans: mole = (78.03 ÷ 77.083 )
= 1.0122854585317 mole of Ammonium acetate.
C2H3O2NH4 (Ammonium acetate) grams to mole Conversion Table:
- 79.04 gram of Ammonium acetate = 1.025388217895 mole of Ammonium acetate
- 87.05 gram of Ammonium acetate = 1.1293021807662 mole of Ammonium acetate
- 95.06 gram of Ammonium acetate = 1.2332161436374 mole of Ammonium acetate
- 103.07 gram of Ammonium acetate = 1.3371301065086 mole of Ammonium acetate
- 111.08 gram of Ammonium acetate = 1.4410440693798 mole of Ammonium acetate
- 119.09 gram of Ammonium acetate = 1.544958032251 mole of Ammonium acetate
- 127.1 gram of Ammonium acetate = 1.6488719951221 mole of Ammonium acetate
- 135.11 gram of Ammonium acetate = 1.7527859579933 mole of Ammonium acetate
- 143.12 gram of Ammonium acetate = 1.8566999208645 mole of Ammonium acetate
- 151.13 gram of Ammonium acetate = 1.9606138837357 mole of Ammonium acetate
- 159.14 gram of Ammonium acetate = 2.0645278466069 mole of Ammonium acetate
- 167.15 gram of Ammonium acetate = 2.1684418094781 mole of Ammonium acetate
- 175.16 gram of Ammonium acetate = 2.2723557723493 mole of Ammonium acetate
- 183.17 gram of Ammonium acetate = 2.3762697352205 mole of Ammonium acetate
- 191.18 gram of Ammonium acetate = 1.4410440693798 mole of Ammonium acetate
- 199.19 gram of Ammonium acetate = 2.5840976609629 mole of Ammonium acetate
- 207.2 gram of Ammonium acetate = 2.688011623834 mole of Ammonium acetate
- 215.21 gram of Ammonium acetate = 2.7919255867052 mole of Ammonium acetate
- 223.22 gram of Ammonium acetate = 2.8958395495764 mole of Ammonium acetate
- 231.23 gram of Ammonium acetate = 2.9997535124476 mole of Ammonium acetate
- 239.24 gram of Ammonium acetate = 3.1036674753188 mole of Ammonium acetate
- 247.25 gram of Ammonium acetate = 3.20758143819 mole of Ammonium acetate
- 255.26 gram of Ammonium acetate = 3.3114954010612 mole of Ammonium acetate
- 263.27 gram of Ammonium acetate = 3.4154093639324 mole of Ammonium acetate
- 271.28 gram of Ammonium acetate = 3.5193233268036 mole of Ammonium acetate
- 279.29 gram of Ammonium acetate = 3.6232372896748 mole of Ammonium acetate
- 287.3 gram of Ammonium acetate = 3.727151252546 mole of Ammonium acetate
- 295.31 gram of Ammonium acetate = 3.8310652154171 mole of Ammonium acetate
- 303.32 gram of Ammonium acetate = 3.9349791782883 mole of Ammonium acetate
- 311.33 gram of Ammonium acetate = 4.0388931411595 mole of Ammonium acetate
C2H3O2NH4 (Ammonium acetate) mole to grams conversion:
If we know the mole number of Ammonium acetate and we want to calculate grams then we again need molecular mass of C2H3O2NH4. We know that the molecular mass of C2H3O2NH4 is 77.083. To calculate grams we need to multiply mole numbers with molecular mass of Ammonium acetate. If molecular mass of C2H3O2NH4 is M(C2H3O2NH4) and mole number is m(C2H3O2NH4) then
m(C2H3O2NH4) = (mole number of C2H3O2NH4 × molecular mass )
= {m(C2H3O2NH4) × M(C2H3O2NH4)}
Example: A sample of C2H3O2NH4 has 0.04 mole. We have to calculate how much grams of Ammonium acetate it equivalent is.
Ans: Here mole number of C2H3O2NH4, m(C2H3O2NH4) = 0.04
Molecular weight of C2H3O2NH4, M(C2H3O2NH4) = 77.083
So, gram weight = ( 0.04 × 77.083 )
= 3.08332 gram
C2H3O2NH4 (Ammonium acetate) mole to gram Conversion Table:
- 1.02 mole of Ammonium acetate = 78.62466 gram of Ammonium acetate
- 1.32 mole of Ammonium acetate = 101.74956 gram of Ammonium acetate
- 1.62 mole of Ammonium acetate = 124.87446 gram of Ammonium acetate
- 1.92 mole of Ammonium acetate = 147.99936 gram of Ammonium acetate
- 2.22 mole of Ammonium acetate = 171.12426 gram of Ammonium acetate
- 2.52 mole of Ammonium acetate = 194.24916 gram of Ammonium acetate
- 2.82 mole of Ammonium acetate = 217.37406 gram of Ammonium acetate
- 3.12 mole of Ammonium acetate = 240.49896 gram of Ammonium acetate
- 3.42 mole of Ammonium acetate = 263.62386 gram of Ammonium acetate
- 3.72 mole of Ammonium acetate = 286.74876 gram of Ammonium acetate
- 4.02 mole of Ammonium acetate = 309.87366 gram of Ammonium acetate
- 4.32 mole of Ammonium acetate = 332.99856 gram of Ammonium acetate
- 4.62 mole of Ammonium acetate = 356.12346 gram of Ammonium acetate
- 4.92 mole of Ammonium acetate = 379.24836 gram of Ammonium acetate
- 5.22 mole of Ammonium acetate = 402.37326 gram of Ammonium acetate
- 5.52 mole of Ammonium acetate = 425.49816 gram of Ammonium acetate
- 5.82 mole of Ammonium acetate = 448.62306 gram of Ammonium acetate
- 6.12 mole of Ammonium acetate = 471.74796 gram of Ammonium acetate
- 6.42 mole of Ammonium acetate = 494.87286 gram of Ammonium acetate
- 6.72 mole of Ammonium acetate = 517.99776 gram of Ammonium acetate
- 7.02 mole of Ammonium acetate = 541.12266 gram of Ammonium acetate
- 7.32 mole of Ammonium acetate = 564.24756 gram of Ammonium acetate
- 7.62 mole of Ammonium acetate = 587.37246 gram of Ammonium acetate
- 7.92 mole of Ammonium acetate = 610.49736 gram of Ammonium acetate
- 8.22 mole of Ammonium acetate = 633.62226 gram of Ammonium acetate
- 8.52 mole of Ammonium acetate = 656.74716 gram of Ammonium acetate
- 8.82 mole of Ammonium acetate = 679.87206 gram of Ammonium acetate
- 9.12 mole of Ammonium acetate = 702.99696 gram of Ammonium acetate
- 9.42 mole of Ammonium acetate = 726.12186 gram of Ammonium acetate
- 9.72 mole of Ammonium acetate = 749.24676 gram of Ammonium acetate
How to Calculate Molecular Mass of Ammonium acetate (C2H3O2NH4):
For calculating molecular mass of Ammonium acetate we need atomic mass of carbon, hydrogen, oxygen and nitrogen. We know that atomic masses of carbon (C), hydrogen (H), oxygen (O) and nitrogen (N) are 12.011, 1.00797, 15.9994 and 14.0067 respectively. So molecular mass of Ammonium acetate = [{atomic mass of carbon (C) × 2} + {atomic mass of hydrogen (H) × 7} + {atomic mass of oxygen (O) × 2} + nitrogen (N)]
= {(12.011× 2) + (1.00797 × 7) + (15.9994 × 2) + 14.0067 }
= 77.08329 gram