BaSO4 (Barium sulphate) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of BaSO4 (Barium sulphate). Suppose the molecular weight of BaSO4 is M(BaSO4). Now we have to divide the gram weight by molecular mass of Barium sulphate. Then the result gives us a mole number.
mole number of BaSO4 (Barium sulphate) = {(grams weight of BaSO4) ÷ Molecular mass of BaSO4}
= {w÷ M(BaSO4)} [suppose w is grams weight of Barium sulphate ]
Example: Suppose a sample of BaSO4 has 243.07 grams. Now we have to calculate the mole number of the BaSO4.
Ans: mole = (240.8 ÷ 233.38 )
= 1.0317936412717 mole of Barium sulphate.
BaSO4 (Barium sulphate) grams to mole Conversion Table:
- 243.07 gram of Barium sulphate = 1.0415202673751 mole of Barium sulphate
- 248.08 gram of Barium sulphate = 1.0629874025195 mole of Barium sulphate
- 253.09 gram of Barium sulphate = 1.0844545376639 mole of Barium sulphate
- 258.1 gram of Barium sulphate = 1.1059216728083 mole of Barium sulphate
- 263.11 gram of Barium sulphate = 1.1273888079527 mole of Barium sulphate
- 268.12 gram of Barium sulphate = 1.1488559430971 mole of Barium sulphate
- 273.13 gram of Barium sulphate = 1.1703230782415 mole of Barium sulphate
- 278.14 gram of Barium sulphate = 1.1917902133859 mole of Barium sulphate
- 283.15 gram of Barium sulphate = 1.2132573485303 mole of Barium sulphate
- 288.16 gram of Barium sulphate = 1.2347244836747 mole of Barium sulphate
- 293.17 gram of Barium sulphate = 1.2561916188191 mole of Barium sulphate
- 298.18 gram of Barium sulphate = 1.2776587539635 mole of Barium sulphate
- 303.19 gram of Barium sulphate = 1.2991258891079 mole of Barium sulphate
- 308.2 gram of Barium sulphate = 1.3205930242523 mole of Barium sulphate
- 313.21 gram of Barium sulphate = 1.1273888079527 mole of Barium sulphate
- 318.22 gram of Barium sulphate = 1.3635272945411 mole of Barium sulphate
- 323.23 gram of Barium sulphate = 1.3849944296855 mole of Barium sulphate
- 328.24 gram of Barium sulphate = 1.4064615648299 mole of Barium sulphate
- 333.25 gram of Barium sulphate = 1.4279286999743 mole of Barium sulphate
- 338.26 gram of Barium sulphate = 1.4493958351187 mole of Barium sulphate
- 343.27 gram of Barium sulphate = 1.4708629702631 mole of Barium sulphate
- 348.28 gram of Barium sulphate = 1.4923301054075 mole of Barium sulphate
- 353.29 gram of Barium sulphate = 1.5137972405519 mole of Barium sulphate
- 358.3 gram of Barium sulphate = 1.5352643756963 mole of Barium sulphate
- 363.31 gram of Barium sulphate = 1.5567315108407 mole of Barium sulphate
- 368.32 gram of Barium sulphate = 1.5781986459851 mole of Barium sulphate
- 373.33 gram of Barium sulphate = 1.5996657811295 mole of Barium sulphate
- 378.34 gram of Barium sulphate = 1.6211329162739 mole of Barium sulphate
- 383.35 gram of Barium sulphate = 1.6426000514183 mole of Barium sulphate
- 388.36 gram of Barium sulphate = 1.6640671865627 mole of Barium sulphate
BaSO4 (Barium sulphate) mole to grams conversion:
If we know the mole number of Barium sulphate and we want to calculate grams then we again need molecular mass of BaSO4. We know that the molecular mass of BaSO4 is 233.38. To calculate grams we need to multiply mole numbers with molecular mass of Barium sulphate. If molecular mass of BaSO4 is M(BaSO4) and mole number is m(BaSO4) then
m(BaSO4) = (mole number of BaSO4 × molecular mass )
= {m(BaSO4) × M(BaSO4)}
Example: A sample of BaSO4 has 2.08 mole. We have to calculate how much grams of Barium sulphate it equivalent is.
Ans: Here mole number of BaSO4, m(BaSO4) = 2.08
Molecular weight of BaSO4, M(BaSO4) = 233.38
So, gram weight = ( 2.08 × 233.38 )
= 485.4304 gram
BaSO4 (Barium sulphate) mole to gram Conversion Table:
- 3.04 mole of Barium sulphate = 709.4752 gram of Barium sulphate
- 6.07 mole of Barium sulphate = 1416.6166 gram of Barium sulphate
- 9.1 mole of Barium sulphate = 2123.758 gram of Barium sulphate
- 12.13 mole of Barium sulphate = 2830.8994 gram of Barium sulphate
- 15.16 mole of Barium sulphate = 3538.0408 gram of Barium sulphate
- 18.19 mole of Barium sulphate = 4245.1822 gram of Barium sulphate
- 21.22 mole of Barium sulphate = 4952.3236 gram of Barium sulphate
- 24.25 mole of Barium sulphate = 5659.465 gram of Barium sulphate
- 27.28 mole of Barium sulphate = 6366.6064 gram of Barium sulphate
- 30.31 mole of Barium sulphate = 7073.7478 gram of Barium sulphate
- 33.34 mole of Barium sulphate = 7780.8892 gram of Barium sulphate
- 36.37 mole of Barium sulphate = 8488.0306 gram of Barium sulphate
- 39.4 mole of Barium sulphate = 9195.172 gram of Barium sulphate
- 42.43 mole of Barium sulphate = 9902.3134 gram of Barium sulphate
- 45.46 mole of Barium sulphate = 10609.4548 gram of Barium sulphate
- 48.49 mole of Barium sulphate = 11316.5962 gram of Barium sulphate
- 51.52 mole of Barium sulphate = 12023.7376 gram of Barium sulphate
- 54.55 mole of Barium sulphate = 12730.879 gram of Barium sulphate
- 57.58 mole of Barium sulphate = 13438.0204 gram of Barium sulphate
- 60.61 mole of Barium sulphate = 14145.1618 gram of Barium sulphate
- 63.64 mole of Barium sulphate = 14852.3032 gram of Barium sulphate
- 66.67 mole of Barium sulphate = 15559.4446 gram of Barium sulphate
- 69.7 mole of Barium sulphate = 16266.586 gram of Barium sulphate
- 72.73 mole of Barium sulphate = 16973.7274 gram of Barium sulphate
- 75.76 mole of Barium sulphate = 17680.8688 gram of Barium sulphate
- 78.79 mole of Barium sulphate = 18388.0102 gram of Barium sulphate
- 81.82 mole of Barium sulphate = 19095.1516 gram of Barium sulphate
- 84.85 mole of Barium sulphate = 19802.293 gram of Barium sulphate
- 87.88 mole of Barium sulphate = 20509.4344 gram of Barium sulphate
- 90.91 mole of Barium sulphate = 21216.5758 gram of Barium sulphate
How to Calculate Molecular Mass of Barium sulphate (BaSO4):
For calculating molecular mass of Barium sulphate we need atomic mass of barium, sulphur and oxygen. We know that atomic masses of barium (Ba), sulphur (S) and oxygen (O) are 137.33, 32.06 and 15.9994 respectively. So molecular mass of Barium sulphate = [atomic mass of barium (Ba) + atomic mass of sulphur (S) + {atomic mass of oxygen (O) × 4}]
= {137.33 + 32.06 + (15.9994× 4)}
= 233.3876 gram