NH4Br (Ammonium bromide) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of NH4Br (Ammonium bromide). Suppose the molecular weight of NH4Br is M(NH4Br). Now we have to divide the gram weight by the molecular mass of Ammonium bromide. Then the result gives us a mole number of NH4Br (Ammonium bromide).
mole number of NH4Br (Ammonium bromide) = {(grams weight of NH4Br) ÷ Molecular mass of NH4Br}
= {w÷ M(NH4Br)} [suppose w is grams weight of Ammonium bromide ]
Example: Suppose a sample of NH4Br has 100.828 grams. Now we have to calculate the mole number of the NH4Br.
Ans: mole = (104.243 ÷ 97.943 )
= 1.0643231267166 mole of Ammonium bromide.
NH4Br (Ammonium bromide) grams to mole Conversion Table:
- 100.828 gram of Ammonium bromide = 1.0294559080281 moles of Ammonium bromide
- 103.859 gram of Ammonium bromide = 1.0604024789929 moles of Ammonium bromide
- 106.89 gram of Ammonium bromide = 1.0913490499576 moles of Ammonium bromide
- 109.921 gram of Ammonium bromide = 1.1222956209224 moles of Ammonium bromide
- 112.952 gram of Ammonium bromide = 1.1532421918871 moles of Ammonium bromide
- 115.983 gram of Ammonium bromide = 1.1841887628519 moles of Ammonium bromide
- 119.014 gram of Ammonium bromide = 1.2151353338166 moles of Ammonium bromide
- 122.045 gram of Ammonium bromide = 1.2460819047814 moles of Ammonium bromide
- 125.076 gram of Ammonium bromide = 1.2770284757461 moles of Ammonium bromide
- 128.107 gram of Ammonium bromide = 1.3079750467108 moles of Ammonium bromide
- 131.138 gram of Ammonium bromide = 1.3389216176756 moles of Ammonium bromide
- 134.169 gram of Ammonium bromide = 1.3698681886403 moles of Ammonium bromide
- 137.2 gram of Ammonium bromide = 1.4008147596051 moles of Ammonium bromide
- 140.231 gram of Ammonium bromide = 1.4317613305698 moles of Ammonium bromide
- 143.262 gram of Ammonium bromide = 1.1532421918871 moles of Ammonium bromide
- 146.293 gram of Ammonium bromide = 1.4936544724993 moles of Ammonium bromide
- 149.324 gram of Ammonium bromide = 1.5246010434641 moles of Ammonium bromide
- 152.355 gram of Ammonium bromide = 1.5555476144288 moles of Ammonium bromide
- 155.386 gram of Ammonium bromide = 1.5864941853935 moles of Ammonium bromide
- 158.417 gram of Ammonium bromide = 1.6174407563583 moles of Ammonium bromide
- 161.448 gram of Ammonium bromide = 1.648387327323 moles of Ammonium bromide
- 164.479 gram of Ammonium bromide = 1.6793338982878 moles of Ammonium bromide
- 167.51 gram of Ammonium bromide = 1.7102804692525 moles of Ammonium bromide
- 170.541 gram of Ammonium bromide = 1.7412270402173 moles of Ammonium bromide
- 173.572 gram of Ammonium bromide = 1.772173611182 moles of Ammonium bromide
- 176.603 gram of Ammonium bromide = 1.8031201821468 moles of Ammonium bromide
- 179.634 gram of Ammonium bromide = 1.8340667531115 moles of Ammonium bromide
- 182.665 gram of Ammonium bromide = 1.8650133240763 moles of Ammonium bromide
- 185.696 gram of Ammonium bromide = 1.895959895041 moles of Ammonium bromide
- 188.727 gram of Ammonium bromide = 1.9269064660057 moles of Ammonium bromide
NH4Br (Ammonium bromide) mole to grams conversion:
If we know the mole number of Ammonium bromide and we want to calculate grams then we again need molecular mass of NH4Br. We know that the molecular mass of NH4Br is 97.943. To calculate grams we need to multiply mole numbers of NH4Br with molecular mass of NH4Br. If molecular mass of NH4Br is M(NH4Br) and mole number is m(NH4Br) then
m(NH4Br) = (mole number of NH4Br × molecular mass )
= {m(NH4Br) × M(NH4Br)}
Example: A sample of NH4Br has 4.51 mole. We have to calculate how much grams of NH4Br it equivalent is.
Ans: Here mole number of NH4Br, m(NH4Br) = 4.51
Molecular weight of NH4Br, M(NH4Br) = 97.943
So, gram weight = ( 4.51 × 97.943 )
= 441.72293 gram
NH4Br (Ammonium bromide) mole to gram Conversion Table:
- 2.25 mole of Ammonium bromide = 220.37175 gram of Ammonium bromide
- 4.577 mole of Ammonium bromide = 448.285111 gram of Ammonium bromide
- 6.904 mole of Ammonium bromide = 676.198472 gram of Ammonium bromide
- 9.231 mole of Ammonium bromide = 904.111833 gram of Ammonium bromide
- 11.558 mole of Ammonium bromide = 1132.025194 gram of Ammonium bromide
- 13.885 mole of Ammonium bromide = 1359.938555 gram of Ammonium bromide
- 16.212 mole of Ammonium bromide = 1587.851916 gram of Ammonium bromide
- 18.539 mole of Ammonium bromide = 1815.765277 gram of Ammonium bromide
- 20.866 mole of Ammonium bromide = 2043.678638 gram of Ammonium bromide
- 23.193 mole of Ammonium bromide = 2271.591999 gram of Ammonium bromide
- 25.52 mole of Ammonium bromide = 2499.50536 gram of Ammonium bromide
- 27.847 mole of Ammonium bromide = 2727.418721 gram of Ammonium bromide
- 30.174 mole of Ammonium bromide = 2955.332082 gram of Ammonium bromide
- 32.501 mole of Ammonium bromide = 3183.245443 gram of Ammonium bromide
- 34.828 mole of Ammonium bromide = 3411.158804 gram of Ammonium bromide
- 37.155 mole of Ammonium bromide = 3639.072165 gram of Ammonium bromide
- 39.482 mole of Ammonium bromide = 3866.985526 gram of Ammonium bromide
- 41.809 mole of Ammonium bromide = 4094.898887 gram of Ammonium bromide
- 44.136 mole of Ammonium bromide = 4322.812248 gram of Ammonium bromide
- 46.463 mole of Ammonium bromide = 4550.725609 gram of Ammonium bromide
- 48.79 mole of Ammonium bromide = 4778.63897 gram of Ammonium bromide
- 51.117 mole of Ammonium bromide = 5006.552331 gram of Ammonium bromide
- 53.444 mole of Ammonium bromide = 5234.465692 gram of Ammonium bromide
- 55.771 mole of Ammonium bromide = 5462.379053 gram of Ammonium bromide
- 58.098 mole of Ammonium bromide = 5690.292414 gram of Ammonium bromide
- 60.425 mole of Ammonium bromide = 5918.205775 gram of Ammonium bromide
- 62.752 mole of Ammonium bromide = 6146.119136 gram of Ammonium bromide
- 65.079 mole of Ammonium bromide = 6374.032497 gram of Ammonium bromide
- 67.406 mole of Ammonium bromide = 6601.945858 gram of Ammonium bromide
- 69.733 mole of Ammonium bromide = 6829.859219 gram of Ammonium bromide
How to Calculate Molecular Mass of Ammonium bromide (NH4Br):
For calculating molecular mass of Ammonium bromide we need atomic mass of nitrogen, hydrogen and bromine. We know that atomic masses of nitrogen (N), hydrogen (H) and bromine (Br) are 14.0067, 1.00797 and 79.904 respectively. So molecular mass of Ammonium bromide = [atomic mass of nitrogen (N) + {atomic mass of hydrogen (H) × 4} + atomic mass of bromine (Br)]
= {14.0067 + (1.00797× 4) + 79.904}
= 97.9425 gram