BaCO3 (Barium carbonate) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of BaCO3 (Barium carbonate). Suppose the molecular weight of BaCO3 is M(BaCO3). Now we have to divide the gram weight by the molecular mass of Barium carbonate. Then the result gives us a mole number of BaCO3 (Barium carbonate).
mole number of BaCO3 (Barium carbonate) = {(grams weight of BaCO3) ÷ Molecular mass of BaCO3}
= {w÷ M(BaCO3)} [suppose w is grams weight of Barium carbonate ]
Example: Suppose a sample of BaCO3 has 200.325 grams. Now we have to calculate the mole number of the BaCO3.
Ans: mole = (207.04 ÷ 197.34 )
= 1.0491537448059 mole of Barium carbonate.
BaCO3 (Barium carbonate) grams to mole Conversion Table:
- 200.325 gram of Barium carbonate = 1.0151261781697 moles of Barium carbonate
- 205.356 gram of Barium carbonate = 1.0406202493159 moles of Barium carbonate
- 210.387 gram of Barium carbonate = 1.0661143204621 moles of Barium carbonate
- 215.418 gram of Barium carbonate = 1.0916083916084 moles of Barium carbonate
- 220.449 gram of Barium carbonate = 1.1171024627546 moles of Barium carbonate
- 225.48 gram of Barium carbonate = 1.1425965339009 moles of Barium carbonate
- 230.511 gram of Barium carbonate = 1.1680906050471 moles of Barium carbonate
- 235.542 gram of Barium carbonate = 1.1935846761934 moles of Barium carbonate
- 240.573 gram of Barium carbonate = 1.2190787473396 moles of Barium carbonate
- 245.604 gram of Barium carbonate = 1.2445728184859 moles of Barium carbonate
- 250.635 gram of Barium carbonate = 1.2700668896321 moles of Barium carbonate
- 255.666 gram of Barium carbonate = 1.2955609607784 moles of Barium carbonate
- 260.697 gram of Barium carbonate = 1.3210550319246 moles of Barium carbonate
- 265.728 gram of Barium carbonate = 1.3465491030708 moles of Barium carbonate
- 270.759 gram of Barium carbonate = 1.1171024627546 moles of Barium carbonate
- 275.79 gram of Barium carbonate = 1.3975372453633 moles of Barium carbonate
- 280.821 gram of Barium carbonate = 1.4230313165096 moles of Barium carbonate
- 285.852 gram of Barium carbonate = 1.4485253876558 moles of Barium carbonate
- 290.883 gram of Barium carbonate = 1.4740194588021 moles of Barium carbonate
- 295.914 gram of Barium carbonate = 1.4995135299483 moles of Barium carbonate
- 300.945 gram of Barium carbonate = 1.5250076010946 moles of Barium carbonate
- 305.976 gram of Barium carbonate = 1.5505016722408 moles of Barium carbonate
- 311.007 gram of Barium carbonate = 1.575995743387 moles of Barium carbonate
- 316.038 gram of Barium carbonate = 1.6014898145333 moles of Barium carbonate
- 321.069 gram of Barium carbonate = 1.6269838856795 moles of Barium carbonate
- 326.1 gram of Barium carbonate = 1.6524779568258 moles of Barium carbonate
- 331.131 gram of Barium carbonate = 1.677972027972 moles of Barium carbonate
- 336.162 gram of Barium carbonate = 1.7034660991183 moles of Barium carbonate
- 341.193 gram of Barium carbonate = 1.7289601702645 moles of Barium carbonate
- 346.224 gram of Barium carbonate = 1.7544542414108 moles of Barium carbonate
BaCO3 (Barium carbonate) mole to grams conversion:
If we know the mole number of Barium carbonate and we want to calculate grams then we again need molecular mass of BaCO3. We know that the molecular mass of BaCO3 is 197.34. To calculate grams we need to multiply mole numbers of BaCO3 with molecular mass of BaCO3. If molecular mass of BaCO3 is M(BaCO3) and mole number is m(BaCO3) then
m(BaCO3) = (mole number of BaCO3 × molecular mass )
= {m(BaCO3) × M(BaCO3)}
Example: A sample of BaCO3 has 4.16 mole. We have to calculate how much grams of BaCO3 it equivalent is.
Ans: Here mole number of BaCO3, m(BaCO3) = 4.16
Molecular weight of BaCO3, M(BaCO3) = 197.34
So, gram weight = ( 4.16 × 197.34 )
= 820.9344 gram
BaCO3 (Barium carbonate) mole to gram Conversion Table:
- 4.46 mole of Barium carbonate = 880.1364 gram of Barium carbonate
- 5.325 mole of Barium carbonate = 1050.8355 gram of Barium carbonate
- 6.19 mole of Barium carbonate = 1221.5346 gram of Barium carbonate
- 7.055 mole of Barium carbonate = 1392.2337 gram of Barium carbonate
- 7.92 mole of Barium carbonate = 1562.9328 gram of Barium carbonate
- 8.785 mole of Barium carbonate = 1733.6319 gram of Barium carbonate
- 9.65 mole of Barium carbonate = 1904.331 gram of Barium carbonate
- 10.515 mole of Barium carbonate = 2075.0301 gram of Barium carbonate
- 11.38 mole of Barium carbonate = 2245.7292 gram of Barium carbonate
- 12.245 mole of Barium carbonate = 2416.4283 gram of Barium carbonate
- 13.11 mole of Barium carbonate = 2587.1274 gram of Barium carbonate
- 13.975 mole of Barium carbonate = 2757.8265 gram of Barium carbonate
- 14.84 mole of Barium carbonate = 2928.5256 gram of Barium carbonate
- 15.705 mole of Barium carbonate = 3099.2247 gram of Barium carbonate
- 16.57 mole of Barium carbonate = 3269.9238 gram of Barium carbonate
- 17.435 mole of Barium carbonate = 3440.6229 gram of Barium carbonate
- 18.3 mole of Barium carbonate = 3611.322 gram of Barium carbonate
- 19.165 mole of Barium carbonate = 3782.0211 gram of Barium carbonate
- 20.03 mole of Barium carbonate = 3952.7202 gram of Barium carbonate
- 20.895 mole of Barium carbonate = 4123.4193 gram of Barium carbonate
- 21.76 mole of Barium carbonate = 4294.1184 gram of Barium carbonate
- 22.625 mole of Barium carbonate = 4464.8175 gram of Barium carbonate
- 23.49 mole of Barium carbonate = 4635.5166 gram of Barium carbonate
- 24.355 mole of Barium carbonate = 4806.2157 gram of Barium carbonate
- 25.22 mole of Barium carbonate = 4976.9148 gram of Barium carbonate
- 26.085 mole of Barium carbonate = 5147.6139 gram of Barium carbonate
- 26.95 mole of Barium carbonate = 5318.313 gram of Barium carbonate
- 27.815 mole of Barium carbonate = 5489.0121 gram of Barium carbonate
- 28.68 mole of Barium carbonate = 5659.7112 gram of Barium carbonate
- 29.545 mole of Barium carbonate = 5830.4103 gram of Barium carbonate
How to Calculate Molecular Mass of Barium carbonate (BaCO3):
For calculating molecular mass of Barium carbonate we need atomic mass of barium, carbon and oxygen. We know that atomic masses of barium (Ba), carbon (C) and oxygen (O) are 137.33, 12.011 and 15.9994 respectively. So molecular mass of Barium carbonate = [atomic mass of barium (Ba) + atomic mass of carbon (C) + {atomic mass of oxygen (O) × 3}]
= {137.33 + 12.011 + (15.9994 × 3)}
= 197.339 gram