Na3C6H5O7 (Sodium citrate) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of Na3C6H5O7 (Sodium citrate). Suppose the molecular weight of Na3C6H5O7 is M(Na3C6H5O7). Now we have to divide the gram weight by the molecular mass of Sodium citrate. Then the result gives us a mole number of Na3C6H5O7 (Sodium citrate).
mole number of Na3C6H5O7 (Sodium citrate) = {(grams weight of Na3C6H5O7) ÷ Molecular mass of Na3C6H5O7}
= {w÷ M(Na3C6H5O7)} [suppose w is grams weight of Sodium citrate ]
Example: Suppose a sample of Na3C6H5O7 has 263.545 grams. Now we have to calculate the mole number of the Na3C6H5O7.
Ans: mole = (264.86 ÷ 258.06 )
= 1.0263504611331 mole of Sodium citrate.
Na3C6H5O7 (Sodium citrate) grams to mole Conversion Table:
- 263.545 gram of Sodium citrate = 1.0212547469581 moles of Sodium citrate
- 266.306 gram of Sodium citrate = 1.0319538091917 moles of Sodium citrate
- 269.067 gram of Sodium citrate = 1.0426528714253 moles of Sodium citrate
- 271.828 gram of Sodium citrate = 1.0533519336588 moles of Sodium citrate
- 274.589 gram of Sodium citrate = 1.0640509958924 moles of Sodium citrate
- 277.35 gram of Sodium citrate = 1.074750058126 moles of Sodium citrate
- 280.111 gram of Sodium citrate = 1.0854491203596 moles of Sodium citrate
- 282.872 gram of Sodium citrate = 1.0961481825932 moles of Sodium citrate
- 285.633 gram of Sodium citrate = 1.1068472448268 moles of Sodium citrate
- 288.394 gram of Sodium citrate = 1.1175463070604 moles of Sodium citrate
- 291.155 gram of Sodium citrate = 1.128245369294 moles of Sodium citrate
- 293.916 gram of Sodium citrate = 1.1389444315276 moles of Sodium citrate
- 296.677 gram of Sodium citrate = 1.1496434937611 moles of Sodium citrate
- 299.438 gram of Sodium citrate = 1.1603425559947 moles of Sodium citrate
- 302.199 gram of Sodium citrate = 1.0640509958924 moles of Sodium citrate
- 304.96 gram of Sodium citrate = 1.1817406804619 moles of Sodium citrate
- 307.721 gram of Sodium citrate = 1.1924397426955 moles of Sodium citrate
- 310.482 gram of Sodium citrate = 1.2031388049291 moles of Sodium citrate
- 313.243 gram of Sodium citrate = 1.2138378671627 moles of Sodium citrate
- 316.004 gram of Sodium citrate = 1.2245369293963 moles of Sodium citrate
- 318.765 gram of Sodium citrate = 1.2352359916299 moles of Sodium citrate
- 321.526 gram of Sodium citrate = 1.2459350538634 moles of Sodium citrate
- 324.287 gram of Sodium citrate = 1.256634116097 moles of Sodium citrate
- 327.048 gram of Sodium citrate = 1.2673331783306 moles of Sodium citrate
- 329.809 gram of Sodium citrate = 1.2780322405642 moles of Sodium citrate
- 332.57 gram of Sodium citrate = 1.2887313027978 moles of Sodium citrate
- 335.331 gram of Sodium citrate = 1.2994303650314 moles of Sodium citrate
- 338.092 gram of Sodium citrate = 1.310129427265 moles of Sodium citrate
- 340.853 gram of Sodium citrate = 1.3208284894986 moles of Sodium citrate
- 343.614 gram of Sodium citrate = 1.3315275517322 moles of Sodium citrate
Na3C6H5O7 (Sodium citrate) mole to grams conversion:
If we know the mole number of Sodium citrate and we want to calculate grams then we again need molecular mass of Na3C6H5O7. We know that the molecular mass of Na3C6H5O7 is 258.06. To calculate grams we need to multiply mole numbers of Na3C6H5O7 with molecular mass of Na3C6H5O7. If molecular mass of Na3C6H5O7 is M(Na3C6H5O7) and mole number is m(Na3C6H5O7) then
m(Na3C6H5O7) = (mole number of Na3C6H5O7 × molecular mass )
= {m(Na3C6H5O7) × M(Na3C6H5O7)}
Example: A sample of Na3C6H5O7 has 5.21 mole. We have to calculate how much grams of Na3C6H5O7 it equivalent is.
Ans: Here mole number of Na3C6H5O7, m(Na3C6H5O7) = 5.21
Molecular weight of Na3C6H5O7, M(Na3C6H5O7) = 258.06
So, gram weight = ( 5.21 × 258.06 )
= 1344.4926 gram
Na3C6H5O7 (Sodium citrate) mole to gram Conversion Table:
- 5.61 mole of Sodium citrate = 1447.7166 gram of Sodium citrate
- 6.41 mole of Sodium citrate = 1654.1646 gram of Sodium citrate
- 7.21 mole of Sodium citrate = 1860.6126 gram of Sodium citrate
- 8.01 mole of Sodium citrate = 2067.0606 gram of Sodium citrate
- 8.81 mole of Sodium citrate = 2273.5086 gram of Sodium citrate
- 9.61 mole of Sodium citrate = 2479.9566 gram of Sodium citrate
- 10.41 mole of Sodium citrate = 2686.4046 gram of Sodium citrate
- 11.21 mole of Sodium citrate = 2892.8526 gram of Sodium citrate
- 12.01 mole of Sodium citrate = 3099.3006 gram of Sodium citrate
- 12.81 mole of Sodium citrate = 3305.7486 gram of Sodium citrate
- 13.61 mole of Sodium citrate = 3512.1966 gram of Sodium citrate
- 14.41 mole of Sodium citrate = 3718.6446 gram of Sodium citrate
- 15.21 mole of Sodium citrate = 3925.0926 gram of Sodium citrate
- 16.01 mole of Sodium citrate = 4131.5406 gram of Sodium citrate
- 16.81 mole of Sodium citrate = 4337.9886 gram of Sodium citrate
- 17.61 mole of Sodium citrate = 4544.4366 gram of Sodium citrate
- 18.41 mole of Sodium citrate = 4750.8846 gram of Sodium citrate
- 19.21 mole of Sodium citrate = 4957.3326 gram of Sodium citrate
- 20.01 mole of Sodium citrate = 5163.7806 gram of Sodium citrate
- 20.81 mole of Sodium citrate = 5370.2286 gram of Sodium citrate
- 21.61 mole of Sodium citrate = 5576.6766 gram of Sodium citrate
- 22.41 mole of Sodium citrate = 5783.1246 gram of Sodium citrate
- 23.21 mole of Sodium citrate = 5989.5726 gram of Sodium citrate
- 24.01 mole of Sodium citrate = 6196.0206 gram of Sodium citrate
- 24.81 mole of Sodium citrate = 6402.4686 gram of Sodium citrate
- 25.61 mole of Sodium citrate = 6608.9166 gram of Sodium citrate
- 26.41 mole of Sodium citrate = 6815.3646 gram of Sodium citrate
- 27.21 mole of Sodium citrate = 7021.8126 gram of Sodium citrate
- 28.01 mole of Sodium citrate = 7228.2606 gram of Sodium citrate
- 28.81 mole of Sodium citrate = 7434.7086 gram of Sodium citrate
How to Calculate Molecular Mass of Sodium citrate (Na3C6H5O7):
For calculating molecular mass of Sodium citrate we need atomic mass of sodium, carbon, hydrogen and oxygen. We know that atomic masses of sodium (Na), carbon (C), hydrogen (H) and oxygen (O) are 22.989769, 12.011, 1.00797 and 15.9994 respectively. So molecular mass of Sodium citrate = [{atomic mass of sodium (Na) × 3} + {atomic mass of carbon (C) × 6} + {atomic mass of hydrogen (H) × 5} + {atomic mass of oxygen (O) × 7}]
= {(22.989769× 3) + (12.011 × 6) + (1.00797× 5) + (15.9994 × 7)}
= 258.07 gram