NH4OH (Ammonium hydroxide) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of NH4OH (Ammonium hydroxide). Suppose the molecular weight of NH4OH is M(NH4OH). Now we have to divide the gram weight by molecular mass of Ammonium hydroxide. Then the result gives us a mole number.
mole number of NH4OH (Ammonium hydroxide) = {(grams weight of NH4OH) ÷ Molecular mass of NH4OH}
= {w÷ M(NH4OH)} [suppose w is grams weight of Ammonium hydroxide ]
Example: Suppose a sample of NH4OH has 36.91 grams. Now we have to calculate the mole number of the NH4OH.
Ans: mole = (35.056 ÷ 35.046 )
= 1.0002853392684 mole of Ammonium hydroxide.
NH4OH (Ammonium hydroxide) grams to mole Conversion Table:
- 36.91 gram of Ammonium hydroxide = 1.0531872396279 mole of Ammonium hydroxide
- 40.45 gram of Ammonium hydroxide = 1.154197340638 mole of Ammonium hydroxide
- 43.99 gram of Ammonium hydroxide = 1.2552074416481 mole of Ammonium hydroxide
- 47.53 gram of Ammonium hydroxide = 1.3562175426582 mole of Ammonium hydroxide
- 51.07 gram of Ammonium hydroxide = 1.4572276436683 mole of Ammonium hydroxide
- 54.61 gram of Ammonium hydroxide = 1.5582377446784 mole of Ammonium hydroxide
- 58.15 gram of Ammonium hydroxide = 1.6592478456885 mole of Ammonium hydroxide
- 61.69 gram of Ammonium hydroxide = 1.7602579466986 mole of Ammonium hydroxide
- 65.23 gram of Ammonium hydroxide = 1.8612680477087 mole of Ammonium hydroxide
- 68.77 gram of Ammonium hydroxide = 1.9622781487188 mole of Ammonium hydroxide
- 72.31 gram of Ammonium hydroxide = 2.0632882497289 mole of Ammonium hydroxide
- 75.85 gram of Ammonium hydroxide = 2.164298350739 mole of Ammonium hydroxide
- 79.39 gram of Ammonium hydroxide = 2.2653084517491 mole of Ammonium hydroxide
- 82.93 gram of Ammonium hydroxide = 2.3663185527592 mole of Ammonium hydroxide
- 86.47 gram of Ammonium hydroxide = 1.4572276436683 mole of Ammonium hydroxide
- 90.01 gram of Ammonium hydroxide = 2.5683387547794 mole of Ammonium hydroxide
- 93.55 gram of Ammonium hydroxide = 2.6693488557895 mole of Ammonium hydroxide
- 97.09 gram of Ammonium hydroxide = 2.7703589567996 mole of Ammonium hydroxide
- 100.63 gram of Ammonium hydroxide = 2.8713690578097 mole of Ammonium hydroxide
- 104.17 gram of Ammonium hydroxide = 2.9723791588198 mole of Ammonium hydroxide
- 107.71 gram of Ammonium hydroxide = 3.0733892598299 mole of Ammonium hydroxide
- 111.25 gram of Ammonium hydroxide = 3.17439936084 mole of Ammonium hydroxide
- 114.79 gram of Ammonium hydroxide = 3.2754094618501 mole of Ammonium hydroxide
- 118.33 gram of Ammonium hydroxide = 3.3764195628602 mole of Ammonium hydroxide
- 121.87 gram of Ammonium hydroxide = 3.4774296638703 mole of Ammonium hydroxide
- 125.41 gram of Ammonium hydroxide = 3.5784397648804 mole of Ammonium hydroxide
- 128.95 gram of Ammonium hydroxide = 3.6794498658905 mole of Ammonium hydroxide
- 132.49 gram of Ammonium hydroxide = 3.7804599669006 mole of Ammonium hydroxide
- 136.03 gram of Ammonium hydroxide = 3.8814700679107 mole of Ammonium hydroxide
- 139.57 gram of Ammonium hydroxide = 3.9824801689208 mole of Ammonium hydroxide
NH4OH (Ammonium hydroxide) mole to grams conversion:
If we know the mole number of Ammonium hydroxide and we want to calculate grams then we again need molecular mass of NH4OH. We know that the molecular mass of NH4OH is 35.046. To calculate grams we need to multiply mole numbers with molecular mass of Ammonium hydroxide. If molecular mass of NH4OH is M(NH4OH) and mole number is m(NH4OH) then
m(NH4OH) = (mole number of NH4OH × molecular mass )
= {m(NH4OH) × M(NH4OH)}
Example: A sample of NH4OH has 1.24 mole. We have to calculate how much grams of Ammonium hydroxide it equivalent is.
Ans: Here mole number of NH4OH, m(NH4OH) = 1.24
Molecular weight of NH4OH, M(NH4OH) = 35.046
So, gram weight = ( 1.24 × 35.046 )
= 43.45704 gram
NH4OH (Ammonium hydroxide) mole to gram Conversion Table:
- 3.04 mole of Ammonium hydroxide = 106.53984 gram of Ammonium hydroxide
- 3.45 mole of Ammonium hydroxide = 120.9087 gram of Ammonium hydroxide
- 3.86 mole of Ammonium hydroxide = 135.27756 gram of Ammonium hydroxide
- 4.27 mole of Ammonium hydroxide = 149.64642 gram of Ammonium hydroxide
- 4.68 mole of Ammonium hydroxide = 164.01528 gram of Ammonium hydroxide
- 5.09 mole of Ammonium hydroxide = 178.38414 gram of Ammonium hydroxide
- 5.5 mole of Ammonium hydroxide = 192.753 gram of Ammonium hydroxide
- 5.91 mole of Ammonium hydroxide = 207.12186 gram of Ammonium hydroxide
- 6.32 mole of Ammonium hydroxide = 221.49072 gram of Ammonium hydroxide
- 6.73 mole of Ammonium hydroxide = 235.85958 gram of Ammonium hydroxide
- 7.14 mole of Ammonium hydroxide = 250.22844 gram of Ammonium hydroxide
- 7.55 mole of Ammonium hydroxide = 264.5973 gram of Ammonium hydroxide
- 7.96 mole of Ammonium hydroxide = 278.96616 gram of Ammonium hydroxide
- 8.37 mole of Ammonium hydroxide = 293.33502 gram of Ammonium hydroxide
- 8.78 mole of Ammonium hydroxide = 307.70388 gram of Ammonium hydroxide
- 9.19 mole of Ammonium hydroxide = 322.07274 gram of Ammonium hydroxide
- 9.6 mole of Ammonium hydroxide = 336.4416 gram of Ammonium hydroxide
- 10.01 mole of Ammonium hydroxide = 350.81046 gram of Ammonium hydroxide
- 10.42 mole of Ammonium hydroxide = 365.17932 gram of Ammonium hydroxide
- 10.83 mole of Ammonium hydroxide = 379.54818 gram of Ammonium hydroxide
- 11.24 mole of Ammonium hydroxide = 393.91704 gram of Ammonium hydroxide
- 11.65 mole of Ammonium hydroxide = 408.2859 gram of Ammonium hydroxide
- 12.06 mole of Ammonium hydroxide = 422.65476 gram of Ammonium hydroxide
- 12.47 mole of Ammonium hydroxide = 437.02362 gram of Ammonium hydroxide
- 12.88 mole of Ammonium hydroxide = 451.39248 gram of Ammonium hydroxide
- 13.29 mole of Ammonium hydroxide = 465.76134 gram of Ammonium hydroxide
- 13.7 mole of Ammonium hydroxide = 480.1302 gram of Ammonium hydroxide
- 14.11 mole of Ammonium hydroxide = 494.49906 gram of Ammonium hydroxide
- 14.52 mole of Ammonium hydroxide = 508.86792 gram of Ammonium hydroxide
- 14.93 mole of Ammonium hydroxide = 523.23678 gram of Ammonium hydroxide
How to Calculate Molecular Mass of Ammonium hydroxide (NH4OH):
For calculating molecular mass of Ammonium hydroxide we need atomic mass of nitrogen, hydrogen and oxygen. We know that atomic masses of nitrogen (N), hydrogen (H) and oxygen (O) are 14.0067, 1.00797 and 15.9994 respectively. So molecular mass of Ammonium hydroxide = [atomic mass of nitrogen (N) + {atomic mass of hydrogen (H) × 5} + atomic mass of oxygen (O)]
= { 14.0067 + (1.00797 × 5) + 15.9994 }
= 35.04959 gram