NH4NO3 (Ammonium nitrate) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of NH4NO3 (Ammonium nitrate). Suppose the molecular weight of NH4NO3 is M(NH4NO3). Now we have to divide the gram weight by molecular mass of Ammonium nitrate. Then the result gives us a mole number.
mole number of NH4NO3 (Ammonium nitrate) = {(grams weight of NH4NO3) ÷ Molecular mass of NH4NO3}
= {w÷ M(NH4NO3)} [suppose w is grams weight of Ammonium nitrate ]
Example: Suppose a sample of NH4NO3 has 80.845 grams. Now we have to calculate the mole number of the NH4NO3.
Ans: mole = (80.021 ÷ 80.043 )
= 0.99972514773309 mole of Ammonium nitrate.
NH4NO3 (Ammonium nitrate) grams to mole Conversion Table:
- 80.845 gram of Ammonium nitrate = 1.0100196144572 mole of Ammonium nitrate
- 90.895 gram of Ammonium nitrate = 1.1355771272941 mole of Ammonium nitrate
- 100.945 gram of Ammonium nitrate = 1.2611346401309 mole of Ammonium nitrate
- 110.995 gram of Ammonium nitrate = 1.3866921529678 mole of Ammonium nitrate
- 121.045 gram of Ammonium nitrate = 1.5122496658046 mole of Ammonium nitrate
- 131.095 gram of Ammonium nitrate = 1.6378071786415 mole of Ammonium nitrate
- 141.145 gram of Ammonium nitrate = 1.7633646914783 mole of Ammonium nitrate
- 151.195 gram of Ammonium nitrate = 1.8889222043152 mole of Ammonium nitrate
- 161.245 gram of Ammonium nitrate = 2.014479717152 mole of Ammonium nitrate
- 171.295 gram of Ammonium nitrate = 2.1400372299889 mole of Ammonium nitrate
- 181.345 gram of Ammonium nitrate = 2.2655947428257 mole of Ammonium nitrate
- 191.395 gram of Ammonium nitrate = 2.3911522556626 mole of Ammonium nitrate
- 201.445 gram of Ammonium nitrate = 2.5167097684994 mole of Ammonium nitrate
- 211.495 gram of Ammonium nitrate = 2.6422672813363 mole of Ammonium nitrate
- 221.545 gram of Ammonium nitrate = 1.5122496658046 mole of Ammonium nitrate
- 231.595 gram of Ammonium nitrate = 2.89338230701 mole of Ammonium nitrate
- 241.645 gram of Ammonium nitrate = 3.0189398198468 mole of Ammonium nitrate
- 251.695 gram of Ammonium nitrate = 3.1444973326837 mole of Ammonium nitrate
- 261.745 gram of Ammonium nitrate = 3.2700548455205 mole of Ammonium nitrate
- 271.795 gram of Ammonium nitrate = 3.3956123583574 mole of Ammonium nitrate
- 281.845 gram of Ammonium nitrate = 3.5211698711942 mole of Ammonium nitrate
- 291.895 gram of Ammonium nitrate = 3.6467273840311 mole of Ammonium nitrate
- 301.945 gram of Ammonium nitrate = 3.7722848968679 mole of Ammonium nitrate
- 311.995 gram of Ammonium nitrate = 3.8978424097048 mole of Ammonium nitrate
- 322.045 gram of Ammonium nitrate = 4.0233999225416 mole of Ammonium nitrate
- 332.095 gram of Ammonium nitrate = 4.1489574353785 mole of Ammonium nitrate
- 342.145 gram of Ammonium nitrate = 4.2745149482153 mole of Ammonium nitrate
- 352.195 gram of Ammonium nitrate = 4.4000724610522 mole of Ammonium nitrate
- 362.245 gram of Ammonium nitrate = 4.525629973889 mole of Ammonium nitrate
- 372.295 gram of Ammonium nitrate = 4.6511874867259 mole of Ammonium nitrate
NH4NO3 (Ammonium nitrate) mole to grams conversion:
If we know the mole number of Ammonium nitrate and we want to calculate grams then we again need molecular mass of NH4NO3. We know that the molecular mass of NH4NO3 is 80.043. To calculate grams we need to multiply mole numbers with molecular mass of Ammonium nitrate. If molecular mass of NH4NO3 is M(NH4NO3) and mole number is m(NH4NO3) then
m(NH4NO3) = (mole number of NH4NO3 × molecular mass )
= {m(NH4NO3) × M(NH4NO3)}
Example: A sample of NH4NO3 has 1.82 mole. We have to calculate how much grams of Ammonium nitrate it equivalent is.
Ans: Here mole number of NH4NO3, m(NH4NO3) = 1.82
Molecular weight of NH4NO3, M(NH4NO3) = 80.043
So, gram weight = ( 1.82 × 80.043 )
= 145.67826 gram
NH4NO3 (Ammonium nitrate) mole to gram Conversion Table:
- 4.01 mole of Ammonium nitrate = 320.97243 gram of Ammonium nitrate
- 6.74 mole of Ammonium nitrate = 539.48982 gram of Ammonium nitrate
- 9.47 mole of Ammonium nitrate = 758.00721 gram of Ammonium nitrate
- 12.2 mole of Ammonium nitrate = 976.5246 gram of Ammonium nitrate
- 14.93 mole of Ammonium nitrate = 1195.04199 gram of Ammonium nitrate
- 17.66 mole of Ammonium nitrate = 1413.55938 gram of Ammonium nitrate
- 20.39 mole of Ammonium nitrate = 1632.07677 gram of Ammonium nitrate
- 23.12 mole of Ammonium nitrate = 1850.59416 gram of Ammonium nitrate
- 25.85 mole of Ammonium nitrate = 2069.11155 gram of Ammonium nitrate
- 28.58 mole of Ammonium nitrate = 2287.62894 gram of Ammonium nitrate
- 31.31 mole of Ammonium nitrate = 2506.14633 gram of Ammonium nitrate
- 34.04 mole of Ammonium nitrate = 2724.66372 gram of Ammonium nitrate
- 36.77 mole of Ammonium nitrate = 2943.18111 gram of Ammonium nitrate
- 39.5 mole of Ammonium nitrate = 3161.6985 gram of Ammonium nitrate
- 42.23 mole of Ammonium nitrate = 3380.21589 gram of Ammonium nitrate
- 44.96 mole of Ammonium nitrate = 3598.73328 gram of Ammonium nitrate
- 47.69 mole of Ammonium nitrate = 3817.25067 gram of Ammonium nitrate
- 50.42 mole of Ammonium nitrate = 4035.76806 gram of Ammonium nitrate
- 53.15 mole of Ammonium nitrate = 4254.28545 gram of Ammonium nitrate
- 55.88 mole of Ammonium nitrate = 4472.80284 gram of Ammonium nitrate
- 58.61 mole of Ammonium nitrate = 4691.32023 gram of Ammonium nitrate
- 61.34 mole of Ammonium nitrate = 4909.83762 gram of Ammonium nitrate
- 64.07 mole of Ammonium nitrate = 5128.35501 gram of Ammonium nitrate
- 66.8 mole of Ammonium nitrate = 5346.8724 gram of Ammonium nitrate
- 69.53 mole of Ammonium nitrate = 5565.38979 gram of Ammonium nitrate
- 72.26 mole of Ammonium nitrate = 5783.90718 gram of Ammonium nitrate
- 74.99 mole of Ammonium nitrate = 6002.42457 gram of Ammonium nitrate
- 77.72 mole of Ammonium nitrate = 6220.94196 gram of Ammonium nitrate
- 80.45 mole of Ammonium nitrate = 6439.45935 gram of Ammonium nitrate
- 83.18 mole of Ammonium nitrate = 6657.97674 gram of Ammonium nitrate
How to Calculate Molecular Mass of Ammonium nitrate (NH4NO3):
For calculating molecular mass of Ammonium nitrate we need atomic mass of nitrogen, hydrogen and oxygen. We know that atomic masses of nitrogen (N), hydrogen (H) and oxygen (O) are 14.0067, 1.00797 and 15.9994 respectively. So molecular mass of Ammonium nitrate = [{atomic mass of nitrogen (N) × 2} + {atomic mass of hydrogen (H) × 4} + {atomic mass of oxygen (O) × 3}]
= {(14.0067 × 2)+ (1.00797 × 4) + (15.9994 × 3)}
= 80.04348 gram