Ba(OH)2 (Barium hydroxide) Gram to mole Conversion:
To convert gram weight to mole we need to find first what is the molecular weight of Ba(OH)2 (Barium hydroxide). Suppose the molecular weight of Ba(OH)2 is M(Ba(OH)2). Now we have to divide the gram weight by molecular mass of Barium hydroxide. Then the result gives us a mole number.
mole number of Ba(OH)2 (Barium hydroxide) = {(grams weight of Ba(OH)2) ÷ Molecular mass of Ba(OH)2}
= {w÷ M(Ba(OH)2)} [suppose w is grams weight of Barium hydroxide ]
Example: Suppose a sample of Ba(OH)2 has 172.224 grams. Now we have to calculate the mole number of the Ba(OH)2.
Ans: mole = (171.87 ÷ 171.341 )
= 1.0030874104855 mole of Barium hydroxide.
Ba(OH)2 (Barium hydroxide) grams to mole Conversion Table:
- 172.224 gram of Barium hydroxide = 1.0051534658955 mole of Barium hydroxide
- 174.894 gram of Barium hydroxide = 1.020736426191 mole of Barium hydroxide
- 177.564 gram of Barium hydroxide = 1.0363193864866 mole of Barium hydroxide
- 180.234 gram of Barium hydroxide = 1.0519023467821 mole of Barium hydroxide
- 182.904 gram of Barium hydroxide = 1.0674853070777 mole of Barium hydroxide
- 185.574 gram of Barium hydroxide = 1.0830682673732 mole of Barium hydroxide
- 188.244 gram of Barium hydroxide = 1.0986512276688 mole of Barium hydroxide
- 190.914 gram of Barium hydroxide = 1.1142341879644 mole of Barium hydroxide
- 193.584 gram of Barium hydroxide = 1.1298171482599 mole of Barium hydroxide
- 196.254 gram of Barium hydroxide = 1.1454001085555 mole of Barium hydroxide
- 198.924 gram of Barium hydroxide = 1.160983068851 mole of Barium hydroxide
- 201.594 gram of Barium hydroxide = 1.1765660291466 mole of Barium hydroxide
- 204.264 gram of Barium hydroxide = 1.1921489894421 mole of Barium hydroxide
- 206.934 gram of Barium hydroxide = 1.2077319497377 mole of Barium hydroxide
- 209.604 gram of Barium hydroxide = 1.0674853070777 mole of Barium hydroxide
- 212.274 gram of Barium hydroxide = 1.2388978703288 mole of Barium hydroxide
- 214.944 gram of Barium hydroxide = 1.2544808306243 mole of Barium hydroxide
- 217.614 gram of Barium hydroxide = 1.2700637909199 mole of Barium hydroxide
- 220.284 gram of Barium hydroxide = 1.2856467512154 mole of Barium hydroxide
- 222.954 gram of Barium hydroxide = 1.301229711511 mole of Barium hydroxide
- 225.624 gram of Barium hydroxide = 1.3168126718065 mole of Barium hydroxide
- 228.294 gram of Barium hydroxide = 1.3323956321021 mole of Barium hydroxide
- 230.964 gram of Barium hydroxide = 1.3479785923976 mole of Barium hydroxide
- 233.634 gram of Barium hydroxide = 1.3635615526932 mole of Barium hydroxide
- 236.304 gram of Barium hydroxide = 1.3791445129887 mole of Barium hydroxide
- 238.974 gram of Barium hydroxide = 1.3947274732843 mole of Barium hydroxide
- 241.644 gram of Barium hydroxide = 1.4103104335798 mole of Barium hydroxide
- 244.314 gram of Barium hydroxide = 1.4258933938754 mole of Barium hydroxide
- 246.984 gram of Barium hydroxide = 1.4414763541709 mole of Barium hydroxide
- 249.654 gram of Barium hydroxide = 1.4570593144665 mole of Barium hydroxide
Ba(OH)2 (Barium hydroxide) mole to grams conversion:
If we know the mole number of Barium hydroxide and we want to calculate grams then we again need molecular mass of Ba(OH)2. We know that the molecular mass of Ba(OH)2 is 171.341. To calculate grams we need to multiply mole numbers with molecular mass of Barium hydroxide. If molecular mass of Ba(OH)2 is M(Ba(OH)2) and mole number is m(Ba(OH)2) then
m(Ba(OH)2) = (mole number of Ba(OH)2 × molecular mass )
= {m(Ba(OH)2) × M(Ba(OH)2)}
Example: A sample of Ba(OH)2 has 2.78 mole. We have to calculate how much grams of Barium hydroxide it equivalent is.
Ans: Here mole number of Ba(OH)2, m(Ba(OH)2) = 2.78
Molecular weight of Ba(OH)2, M(Ba(OH)2) = 171.341
So, gram weight = ( 2.78 × 171.341 )
= 476.32798 gram
Ba(OH)2 (Barium hydroxide) mole to gram Conversion Table:
- 3.74 mole of Barium hydroxide = 640.81534 gram of Barium hydroxide
- 6.86 mole of Barium hydroxide = 1175.39926 gram of Barium hydroxide
- 9.98 mole of Barium hydroxide = 1709.98318 gram of Barium hydroxide
- 13.1 mole of Barium hydroxide = 2244.5671 gram of Barium hydroxide
- 16.22 mole of Barium hydroxide = 2779.15102 gram of Barium hydroxide
- 19.34 mole of Barium hydroxide = 3313.73494 gram of Barium hydroxide
- 22.46 mole of Barium hydroxide = 3848.31886 gram of Barium hydroxide
- 25.58 mole of Barium hydroxide = 4382.90278 gram of Barium hydroxide
- 28.7 mole of Barium hydroxide = 4917.4867 gram of Barium hydroxide
- 31.82 mole of Barium hydroxide = 5452.07062 gram of Barium hydroxide
- 34.94 mole of Barium hydroxide = 5986.65454 gram of Barium hydroxide
- 38.06 mole of Barium hydroxide = 6521.23846 gram of Barium hydroxide
- 41.18 mole of Barium hydroxide = 7055.82238 gram of Barium hydroxide
- 44.3 mole of Barium hydroxide = 7590.4063 gram of Barium hydroxide
- 47.42 mole of Barium hydroxide = 8124.99022 gram of Barium hydroxide
- 50.54 mole of Barium hydroxide = 8659.57414 gram of Barium hydroxide
- 53.66 mole of Barium hydroxide = 9194.15806 gram of Barium hydroxide
- 56.78 mole of Barium hydroxide = 9728.74198 gram of Barium hydroxide
- 59.9 mole of Barium hydroxide = 10263.3259 gram of Barium hydroxide
- 63.02 mole of Barium hydroxide = 10797.90982 gram of Barium hydroxide
- 66.14 mole of Barium hydroxide = 11332.49374 gram of Barium hydroxide
- 69.26 mole of Barium hydroxide = 11867.07766 gram of Barium hydroxide
- 72.38 mole of Barium hydroxide = 12401.66158 gram of Barium hydroxide
- 75.5 mole of Barium hydroxide = 12936.2455 gram of Barium hydroxide
- 78.62 mole of Barium hydroxide = 13470.82942 gram of Barium hydroxide
- 81.74 mole of Barium hydroxide = 14005.41334 gram of Barium hydroxide
- 84.86 mole of Barium hydroxide = 14539.99726 gram of Barium hydroxide
- 87.98 mole of Barium hydroxide = 15074.58118 gram of Barium hydroxide
- 91.1 mole of Barium hydroxide = 15609.1651 gram of Barium hydroxide
- 94.22 mole of Barium hydroxide = 16143.74902 gram of Barium hydroxide
How to Calculate Molecular Mass of Barium hydroxide (Ba(OH)2):
For calculating molecular mass of Barium hydroxide we need atomic mass of barium, oxygen and hydrogen. We know that atomic masses of barium (Ba), oxygen (O) and hydrogen (H) are 137.33, 15.9994 and 1.00797 respectively. So molecular mass of Barium hydroxide = [atomic mass of barium (Ba) + {atomic mass of oxygen (O) + atomic mass of hydrogen (H) } × 2]
= { 137.33 + (15.9994 + 1.00797) × 2}
= 171.34474 gram